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Q. Spotlight $S$ rotates in a horizontal plane with a constant angular velocity of $0.1rads^{- 1}$ . The spot of light $P$ moves along the wall at a distance of $3m$ . The velocity of the spot $P$ when $\theta =45^\circ $ (see. fig.) is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$\text{tan} \theta = \frac{\text{SM}}{\text{PM}}$
$\therefore \text{PM}=\frac{\text{SM}}{\text{tan} \theta }=3cot\theta $ $v=3\left|cosec^{2} \theta \right|\frac{d \theta }{d t}$ For $\theta =45^\circ $ $v=rω=3\times 2\times 0.1=0.6 \, m \, s^{- 1}$