Question

Specific conductance of $0.1\, M$ nitric acid is $6.3 \times 10^{-2} \,ohm ^{-1} cm ^{-1} .$ The molar conductance of the solution is

• A. $630 \,ohm ^{-1} \,cm ^{2}\, mol ^{-1}$
• B. $315 \,ohm ^{-1} \,cm ^{2} mol ^{-1}$
• C. $6.300 \,ohm ^{-1}\,cm ^{2} mol ^{-1}$
• D. $63.0 \,ohm ^{-1} \,cm ^{2} mol ^{-1}$

Answer 1

Answer: (A)

$\kappa=6.3 \times 10^{-2}\, ohm ^{-1} \,cm ^{-1}, C=0.1 M$

$\Lambda_{m}=\kappa \times \frac{1000}{C}=6.3 \times 10^{-2} \times \frac{1000}{0.1}=630\, ohm ^{-1} \,cm ^{2} \,mol ^{-1}$