Question

Specific conductance of $0.1\, M\, NaCl$ solution is $1.01 \times 10^{-2}\, ohm^{-1}\, cm^{-1}$. Its molar conductance in $ohm^{-1}\, cm^2 \,mol^{-1}$ is

• A. $1.01\times10^{2}$
• B. $1.01 \times 10^{3}$
• C. $1.01 \times 10^{4}$
• D. $1.01$

Answer 1

Answer: (A)

$\Lambda_{m}=\frac{\kappa\times1000}{M}$
$=\frac{1.01\times10^{-2}\times1000}{0.1}$
$=1.01\times10^{2}\,ohm^{-1}\,cm^{2}\,mol^{-1}$