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Q. Some equipotential surfaces, which are normal to $x-y$ plane are shown in the adjoining figure. The magnitude of the electric field is $\left(\right.V/cm\left.\right)$ :-
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Equipotential surfaces shown in the figure are equidistant, parallel and have equal potential difference between two consecutive surfaces.This information is clear indication of uniform electric field which is given as
$\left|\right.\overset{ \rightarrow }{E}\left|\right.=-\frac{\Delta V}{\Delta r}=\frac{20 - 10}{B C}=\frac{10}{10 sin 30 ^\circ }$
$\therefore E=\frac{10}{5}=2V/cm$