1. Tardigrade
  2. Question
  3. Chemistry
  4. Some amount of dichloromethane ( CH 2 Cl 2) is added to 671.141 mL of chloroform ( CHCl 3) to prepare 2.6 × 10-3 M solution of CH 2 Cl 2( DCM ). The concentration of DCM is ppm (by mass). Given: Atomic mass: C =12 ; H: 1 ; Cl =35.5 density of CHCl 3=1.49 g cm -3

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Some amount of dichloromethane $\left( CH _2 Cl _2\right)$ is added to $671.141 \,mL$ of chloroform $\left( CHCl _3\right)$ to prepare $2.6 \times 10^{-3} M$ solution of $CH _2 \,Cl _2( DCM )$. The concentration of DCM is____$ ppm $(by mass).
Given: Atomic mass : $C =12 ; H : 1 ; Cl =35.5$ density of $CHCl _3=1.49\, g \,cm ^{-3}$

JEE MainJEE Main 2023Solutions

Solution:

Molarity $=\frac{\text { mole }}{\text { volume }} $
$2.6 \times 10^{-3} =\frac{ x / 85}{0.67141} $
$x =0.148 \,g$
conc. Fo DCM in ppm $=\frac{0.148}{1.49 \times 671.141} \times 10^6 $
$ =148 \,ppm $