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Q. Solution of $|x - 1| \geq|x - 3|$ is

Linear Inequalities

Solution:

$| x -1|$ is the distance of $x$ from $1 .$
$|x-3|$ is the distance of $x$ from $3 .$
The point $x=2$ is equidistant from 1 and 3 .
Hence, the solution consists of all $x \geq 2$.