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Q.
Solution of $( x-1 )^2(x + 4) < 0$ is
Linear Inequalities
Solution:
$(x - 1)^2$ is always positive except when $x = 1$ (and then it is $0$)
$\therefore \quad$ Solution is when $x + 4 < 0$ and $x \ne 1$
i.e. $x < - 4$, $x \ne 1 \therefore x \in \left(-\infty,\,-4\right)$.