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  4. Solution of oxalate is colourless. It is made acidic by adding excess of H+, then titrated with KMnO4. Now at a moment if someone has added large amount of KMnO4, in it then no. of possible products are

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Q. Solution of oxalate is colourless. It is made acidic by adding excess of $H^+$, then titrated with $KMnO_4$. Now at a moment if someone has added large amount of $KMnO_4$, in it then no. of possible products are

The d-and f-Block Elements

Solution:

If $KMnO _4$ was added slowly than option a was correct, but at a moment due to addition of large amount of $KMnO _4$, reduction of whole $KMnO _4$ added does not take place, it also react with $Mn ^{2+}$. which had formed in the solution to give $MnO _2$
$2 MnO _4^{-}+3 Mn ^{2+}+2 H _2 O \longrightarrow 5 MnO _2+4 H ^{+}$