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  4. Solubility of AgCl at 20 oC is 1.435× 10-3g/L. The solubility product of AgCl is

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Q. Solubility of $ AgCl $ at $ 20{{\,}^{o}}C $ is $ 1.435\times {{10}^{-3}}g/L. $ The solubility product of $ AgCl $ is

WBJEEWBJEE 2007

Solution:

$AgCl \rightleftharpoons Ag ^{+}+ Cl ^{-}$
$K_{ sp }=\left[ Ag ^{+}\right]\left[ Cl ^{-}\right]$
$K_{ sp }=S^{2}$
$(S=$ solubility in $mol / L )$
$S=\frac{1.435 \times 10^{-3} g / L }{143.5}=1 \times 10^{-10} mol / L$