Thank you for reporting, we will resolve it shortly
Q.
Sodium metal crystallises in body centred cubic lattice with cell edge $427$ pm. Thus, radius of sodium atom is
The Solid State
Solution:
In $bcc$ structure, radius $(r)$ is related to edge length by
$r =\frac{\sqrt{3}}{4} a$
$ = \frac{\sqrt{3}}{4} \times 427\,pm$
$ = 185.67$
$ = 185\,pm$