Question

$SO _2 Cl _2$ on reaction with excess of water results into acidic mixture
$SO _2 Cl _2+2 H _2 O \rightarrow H _2 SO _4+2 HCl$
16 moles of $NaOH$ is required for the complete neutralisation of the resultant acidic mixture. The number of moles of $SO _2 Cl _2$ used is :

• A. 16
• B. 8
• C. 4
• D. 2

Answer 1

Answer: (C)

Let $n \left( SO _2 Cl _2\right)= x$ moles
$ \therefore n \left( H _2 SO _4\right)= x , n ( HCl )=2 x$
$\Rightarrow n \left( H ^{+}\right)=4 x $
For Neutralisation
$ \Rightarrow n \left( H ^{+}\right)= n \left( OH ^{-}\right) $
$\Rightarrow 4 x =16$
$\Rightarrow x =4$