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  4. SnCl2 gives a precipitate with a solution of HgCl2. In this process HgCl2 is

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Q. $SnCl_2$ gives a precipitate with a solution of $HgCl_2$. In this process $HgCl_2$ is

Redox Reactions

Solution:

In this reaction $ Hg Cl _{2} $ is reduced in $ Hg$

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