Question

Six charges $+ q ,- q ,+ q ,- q ,+ q$ and $- q$ are fixed at the corners of a hexagon of side $d$ as shown in the figure. The work done in bringing a charge $q _0$ to the centre of the hexagon from infinity is : $\left(\varepsilon_0-\right.$ permittivity of free space)

• A. Zero
• B. $\frac{- q ^2}{4 \pi \varepsilon_0 d }$
• C. $\frac{- q ^2}{4 \pi \varepsilon_0 d }\left(3-\frac{1}{\sqrt{2}}\right)$
• D. $\frac{- q ^2}{4 \pi \varepsilon_0 d }\left(6-\frac{1}{\sqrt{2}}\right)$

Answer 1

Answer: (A)

Correct answer is (a) Zero