Question

Six charges each equal to $+Q$ are placed at the corners of a regular hexagon of each side $a$. What is the electric potential at the intersection of the hexagon is ?

• A. $\frac{1}{4\,\pi\,\varepsilon_0}\frac{36\,Q}{x^2}$
• B. $\frac{1}{4\,\pi\,\varepsilon_0}\frac{6\,Q}{x^2}$
• C. $\frac{1}{4\,\pi\,\varepsilon_0}\frac{Q}{x^2}$
• D. Zero

Answer 1

Answer: (D)

The electric field at the centre of the hexagon is zero. Since, due to symmetry in hexagon geometry vector sum of all electric fields by each charge particle cancel out each other.