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Q. Six boys and six girls sit along a line alternately in x ways and along a circle (again alternately) in y ways, then :

Permutations and Combinations

Solution:

$6 ! \cdot 2 \cdot 6 !=x, 5 ! 6 !=y \Rightarrow \frac{x}{y}=\frac{6 ! \cdot 2 \cdot 6 !}{5 ! \cdot 6 !}=12 . $
Hence $x=12 y \Rightarrow D$