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Q. $\sin \left(\cos ^{-1}\left(\tan \left(\frac{\pi}{6}\right)\right)\right)$ is equal to

Inverse Trigonometric Functions

Solution:

$\sin \left(\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)\right)=\sin \left(\sin ^{-1} \sqrt{1-\frac{1}{3}}\right)=\sqrt{\frac{2}{3}}$