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Physics
Seven resistances, each of value 20 Ω , are connected to a 2 V battery as shown in the figure. The ammeter reading will be
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Q. Seven resistances, each of value $20\, \Omega$ , are connected to a $2 V$ battery as shown in the figure. The ammeter reading will be
BITSAT
BITSAT 2018
A
1/10 A
9%
B
3/10 A
12%
C
4/10 A
63%
D
7/10 A
16%
Solution:
In the question seven resistors, each of resistance $20\, \Omega$ are connected in parallel to battery.
Current through each resistor $=\frac{2}{20}=\frac{1}{10} A$
Current through ammeter $=4 \times \frac{1}{10}=\frac{4}{10} A$.