The equivalent circuit of the given circuit is
This is a balanced Wheatstone bridge. Therefore, the arm CD becomes in effective. Hence 5$\Omega$ and 3$\Omega$ are in series and they together are in parallel with (5 + 3) $\Omega$
$\therefore $ Net resistance $=\frac{\left(5+3\right)+\left(5+3\right)}{\left(5+3\right)\times\left(5+3\right)}=4\Omega$