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Q. Seven capacitors, a switch $S$ and a source of emf are connected as shown in the figure. Initially, $S$ is open and all capacitors are uncharged. After $S$ is closed and steady state is attained, the potential difference in volt across the plates of the capacitor $A$ isPhysics Question Image

Electrostatic Potential and Capacitance

Solution:

The equivalent circuit is
image
Above circuit is equivalent to the following circuit :
image
If $q$ be the charge on each capacitor, then
$\frac{q}{21} + \frac{q}{7} + \frac{q}{28} + \frac{q}{3} + \frac{q}{7} = 59$
or $q = 84 \,\mu C$
$\therefore $ Potential difference across
$A = \frac{q}{7} = \frac{84}{7} = 12\,V$