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Q. Separation energy of a hydrogen like ion from its third excited state is $2.25$ times the separation energy of hydrogen atom from its first excited state. Find out the atomic number of this hydrogen like ion.

NTA AbhyasNTA Abhyas 2020Atoms

Solution:

Let the separation energy of the ion be $E$ . Then
$E \, = \, 13.6\times Z^{2}\times \frac{1}{16} \, eV$
and $E_{H}=13.6\times \frac{1}{4} \, eV$
⇒ $\frac{E}{E_{H}}=Z^{2}\times \frac{4}{16}$
⇒ $\frac{2.25 E_{H}}{E_{H}}=\frac{Z^{2}}{4}$
$\Rightarrow Z^{2}=9\Rightarrow Z=3$