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Q. Separation between the first maximum and fifth minimum of a YDSE pattern is $7mm$ and the slits are separated by $0.15mm$ with the screen $50cm$ from the slits, then the wavelength of the light used is

NTA AbhyasNTA Abhyas 2020

Solution:

There are three and a half fringes from first maxima to fifth minima as shown.
Solution
$\Rightarrow \beta =\frac{7 m m}{3 . 5}=2mm\Rightarrow \lambda =\frac{\beta d}{D}=600nm$