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Select $X$ and $Y$ out of $I : MnO _{4}^{-} / OH ^{-}$ and $II : HCO _{3} H$

Alcohols Phenols and Ethers

Solution:

Both products are obtained with dihydroxylation of alkene. The syn addition product is obtained with $I : MnO _{4}^{-} / OH ^{-}$and the anti addition product is obtained with II : $HCO _{3} H$. Thus $X$ is $I : MnO _{4}^{-} / OH ^{-}$and $Y$ is $II : HCO _{3} H$.