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Q.
Select the true statement from the following for metal carbonyls?
Coordination Compounds
Solution:
The overlap of a lone pair on the $C$ atom with the empty hybrid metal orbital forms a metal-to-carbon $\sigma$-bond. The transition metal atom in a metal carbonyl has filled non-bonding $d$-orbitals which are of proper symmetry to overlap with the anti-bonding orbitals of $CO$. The electronic charge is transferred from the filled non-bonding orbitals of the metals to $\pi^{*}$ orbitals of the ligand $CO$. This reduces the bond order of $CO$. The $\pi$ back-bonding strengthens the $M - C$ bond order, it weakens the $C - O$ bond order.