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Q.
Select the dimensional formula of $\frac{B^{2}}{2 \mu _{0}}$
NTA AbhyasNTA Abhyas 2020Physical World, Units and Measurements
Solution:
$\frac{B^{2}}{2 \mu _{0}}=Energy \, density=\frac{E n e r g y}{V o l u m e}$
$\Rightarrow \, \frac{\left[ML^{2} T^{- 2}\right]}{\left[L^{3}\right]}=\left[ML^{- 1} T^{- 2}\right]$