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Q. Select the correct statement for $\Lambda_{ m }=\Lambda_{ m }^{\circ}-A C^{1 / 2}$.

Electrochemistry

Solution:

For strong electrolytes $\Lambda_{ m }=\Lambda_{ m }^{\circ}-A C^{1 / 2}$
If we plot $\Lambda_{ m }$ against $C^{1 / 2}$, we obtain straight line with intercept equal to $\Lambda_{m}^{\circ}$ and slope is equal to $-A$. The constant $A$ depends on the type of electrolyte, i.e. charges on cation and anion produced on dissociation of electrolyte.