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Q. Select correct option for $O-O$ bond order.

NTA AbhyasNTA Abhyas 2022

Solution:

$O_{3}\Rightarrow $
Solution Bond order $=1.5$
$O_{2}^{+}\Rightarrow B.O.=\frac{N_{b} - N_{a}}{2}=\frac{10 - 5}{2}=2.5$
$H_{2}O_{2}\Rightarrow $
Solution
$\Rightarrow B.O.=1.0$
$O_{2}\Rightarrow B.O.=\frac{10 - 6}{2}=2.0$
Correct order:
(2) $\left(2\right)O_{2}^{+}>O_{2}>O_{3}>H_{2}O_{2}$