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  4. Sec-1 ( (2 √2/ 1 + √3) ) =

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Q. $Sec^{-1} ( \frac{2 \sqrt{2}}{ 1 + \sqrt{3}} ) = $

Inverse Trigonometric Functions

Solution:

$\frac{2\sqrt{2}}{\sqrt{3}+1} = \sec15^{\circ}$