Question

$SbF_{5}$ reacts with $XeF_{4}$ to form an adduct. The shapes of cation and anion in the adduct are respectively

• A. Square planar, trigonal bipyramidal
• B. T-shaped, octahedral
• C. Square pyramidal, octahedral
• D. Square planar, octahedral

Answer 1

Answer: (B)

$\text{XeF}_{\text{4}} \, \text{+} \, \text{SbF}_{\text{5}} \rightarrow \text{[XeF}_{\text{3}} \text{]} \, \text{+} \, \text{[SbF}_{\text{6}} \text{]}^{-} \rightarrow \underset{\underset{\text{T-Shaped}}{\text{sp}^{\text{3}} \text{d}}}{\text{[XeF}_{\text{3}} \text{]}^{\text{+}}} \, \text{+} \, \underset{\underset{\text{octahedral}}{\text{sp}^{\text{3}} \text{d}^{\text{2}}}}{\text{[SbF}_{\text{6}} \text{]}^{-}}$

As $\left[\right.XeF_{3}\left]\right.^{+}$ has 3 bond pair and 2 lone pair of electron so it has $sp^{3}d$ hybridisation and T-shape.

$\left[\right.SbF_{6}\left]\right.^{-}$ has 6 bond pair electrons so it is $sp^{3}d^{2}$ hybridise and octahedral in shape.