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Q. Sand is being dropped from a stationary dropper at a rate of $0.5 \,kgs ^{-1}$ on a conveyor belt moving with a velocity of $5\, ms ^{-1}$. The power needed to keep belt moving with the same velocity will be :

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Solution:

Thrust $=\lambda V _{\text {rel }}$
$=2.5 N$
Now, Power $= F \times V =12.5 W$