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Q. Sand drops vertically at the rate of $2\, kg / sec$ on to a conveyor belt moving horizontally with a velocity of $0.2 \,m / sec .$ Then the extra force required to keep the belt moving is

Laws of Motion

Solution:

Force required to keep the belt moving $=F$
$F=v \frac{d m}{d t}=0.2 \times 2=0.4\, N$