Question

Same amount of electric current is passed through solutions of $AgNO_3$ and HCl. If 1.08 g of silver is obtained in the first case, the amount of hydrogen liberated at S.T.P. in the second case is

• A. 112 $cm^3$
• B. 22400 $cm^3$
• C. 224 $cm^3$
• D. 1.008 g

Answer 1

Answer: (A)

$\frac{\text{Mass of} Ag}{\text{Mass of} H_{2}} = \frac{\text{Eq. mass of} Ag}{\text{Eq. mass of} H_{2}} $
$ \frac{1.80}{\text{Mass of} H_{2}} = \frac{108}{1} $
Mass of $H_{2} = \frac{1.80}{108} = 10^{-2}\, g $
$2\, g$ of $H_2$ at S.T.P. occupy $22400 \,cm^3$
$\therefore 10^{-2}\, g$ of $H_2$ at S.T.P. occupy
$= \frac{22400}{2}\times 10^{-2} \,cm^{3} $
$= 112\, cm^{3}$