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  4. Resultant molarity of H + ion in a mixture of 100 mL of 0.1 M H 2 SO 4 and 200 mL of 0.1 M H 3 PO 3 is:

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Q. Resultant molarity of $H ^{+}$ ion in a mixture of $100\, mL$ of $0.1\, M\, H _{2} SO _{4}$ and $200\, mL$ of $0.1\, M\, H _{3} PO _{3}$ is:

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Solution:

$H ^{+}$ (in $H _{2} SO _{4}-$ a dibasic acid $)=0.2\, M$

$H ^{+}\left(\right.$ in $H _{3} PO _{3}-$ a dibasic acid $)=0.2 \,M$

Total $\left[ H ^{+}\right]=\frac{M_{1} V_{1}+M_{2} V_{2}}{V_{1}+V_{2}}$

$=\frac{100 \times 0.2+200 \times 0.2}{300}=0.2 \,M$