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Q. Resonant frequency of a series LCR circuit is 600 Hz. Quality factor of the circuit is 4. Band width is

COMEDKCOMEDK 2008Alternating Current

Solution:

Bandwidth of $LCR $ circuit is given by,
$2 \Delta \omega = \frac{\omega_0}{Q} $ or $2 \Delta \upsilon = \frac{\upsilon_0}{Q}$
Here, $\upsilon_0 = 600 \: Hz , Q = 4 $
$ \therefore $ Band width $ = \frac{600}{4} = 150 \, Hz $