Question

Resolve $\frac{x}{(x+1)(x-1)^2}$ into partial fractions.

• A. $\frac{1}{2(x-1)^2}+\frac{1}{4(x-1)}+\frac{1}{4(x+1)}$
• B. $\frac{-1}{4(x+1)}+\frac{1}{4(x-1)}+\frac{1}{2(x-1)^2}$
• C. $\frac{-1}{4(x-1)}+\frac{1}{4(x+1)}+\frac{1}{2(x-1)^2}$
• D. None of these

Answer 1

Answer: (B)

$\frac{x}{(x+1)(x-1)^2}=\frac{A}{x+1}+\frac{B}{x-1}+\frac{C}{(x-1)^2}$.