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  4. Resistances 1 Ω, 2 Ω and 3 Ω are connected to form a triangle. If a 1.5 V cell of negligible internal resistance is connected across the 3 Ω resistor, the current flowing through this resistor will be

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Q. Resistances $1\, \Omega,\,2\, \Omega$ and $3\, \Omega$ are connected to form a triangle. If a $1.5\, V$ cell of negligible internal resistance is connected across the $3\, \Omega$ resistor, the current flowing through this resistor will be

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Solution:

Here resistors $1$ and $2$ in series and combine $(1,2)$ in parallel with $3$.
So, potential across $(1,2)$ and $3$ will be same i.e $1.5\, V$
Thus, current through $3\, \Omega=\frac{1.5}{3}=0.5\, A$