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Q. Reduction of the metal centre in aqueous permanganate ion involves

JEE AdvancedJEE Advanced 2011

Solution:

In acidic medium
$MnO _{4}^{-}+8 H ^{+}+5 e ^{-} \longrightarrow Mn ^{2+}+4 H _{2} O$
In neutral medium
$MnO _{4}^{-}+2 H _{2} O +3 e ^{-} \longrightarrow MnO _{2}+4 OH ^{-}$
Hence, number of electron loose in acidic and neutral medium 5 and 3 electrons respectively.