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Q.
Reading of ammeter is $2A$ . Find value of $R$ (in $W$ ) .
NTA AbhyasNTA Abhyas 2022
Solution:
$V_{P}=2\times 2=4V$
$\Rightarrow $ Current through $3\Omega=\frac{10 - 4}{3}=2A$
Means no current through $5\Omega$ . $\Rightarrow $ Wheatstone bridge. $\Rightarrow \frac{R^{'}}{3}=\frac{4}{2}\Rightarrow R^{'}=6\Omega$
