1. Tardigrade
  2. Question
  3. Chemistry
  4. RCH2OH arrow KMnO4 / OH-P. What is the compound P?

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $RCH_{2}OH \rightarrow _{}^{KMnO_{4} / OH^{-}}P.$ What is the compound P?

NTA AbhyasNTA Abhyas 2022

Solution:

$RCH_{2}OH \rightarrow _{}^{KMnO_{4} / OH^{-}}R-CH=O \rightarrow _{}^{KMnO_{4} / OH^{-}}R-COOH$
Primary alcohols are oxidized to carboxylic acids with $KMnO_{4}$ in neutral, acidic or basic medium.