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Physics
Ram moves in east direction at a speed of 6 m / s and Shyam moves 30° east of north at a speed of 6 m / s. The magnitude of their relative velocity is
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Q. Ram moves in east direction at a speed of $6\, m / s$ and Shyam moves $30^{\circ}$ east of north at a speed of $6\, m / s$. The magnitude of their relative velocity is
Motion in a Plane
A
$3\, m / s$
B
$6\, m / s$
C
$6 \sqrt{3} m / s$
D
$6 \sqrt{2} m / s$
Solution:
$\left|\vec{V}_{R S}\right|=\sqrt{V_{R}^{2}+V_{S}^{2}-2 V_{R} V_{S} \cos \theta}$
$=\sqrt{6^{2}+6^{2}-2 \times 6^{2} \times \frac{1}{2}}$
$=6\, ms ^{-1}$