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  4. Radius of gyration of disc of mass 50 g and radius 2.5 cm about an axis passing through its center of gravity and perpendicular to the plane is

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Q. Radius of gyration of disc of mass 50 g and radius 2.5 cm about an axis passing through its center of gravity and perpendicular to the plane is

Punjab PMETPunjab PMET 2010System of Particles and Rotational Motion

Solution:

Here mass M = 50 g and radius R = 2.5 cm Required moment of inertia of the disc is given by
$I=\frac{MR^2}{2}=MK^2$
so,$K^2=\frac{R^2}{2}or \, K=\frac{R}{\sqrt{2}}=\frac{2.5}{\sqrt{2}}=\frac{2.5\sqrt{2}}{2}$
= 1.767= 1.77 cm