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Q. Radius of a soap bubble is increased from $R$ to $2R$, work done is this process in terms of surface tension is

Rajasthan PETRajasthan PET 2001

Solution:

$ W=T.\Delta A $
$ =T.[4\pi (2{{n}^{2}}-4\pi {{r}^{2}})] $
$ =12T\pi {{r}^{2}} $