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Q. Radius of $_{13} AI^{27}$ nucleus ($R_0$ = 1.2 fermi) in units of fermi is

COMEDKCOMEDK 2006Nuclei

Solution:

As $R = R_0 (A)^{1/3}$
Here, $R_0 = 1.2 \, fermi, A = 27, R = ?$
$\therefore \, R = 1.2 (27)^{1/3} = 3.6 \, rermi$