$ \frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{t/T}}={{\left( \frac{1}{2} \right)}^{\frac{10}{5}}}={{\left( \frac{1}{2} \right)}^{2}}=\frac{1}{4}=25% $
This is probability of remaining portion of radium. So, probability of decay
$ =(100-25)%=75% $