1. Tardigrade
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  3. Chemistry
  4. R-NH-COH ->[POCl3][ textPyridine] Product In the given reaction, what will be the product?

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Q. $R-NH-COH\ce{ ->[{POCl_3}][{\text{Pyridine}}] }$ Product In the given reaction, what will be the product?

JIPMERJIPMER 2006

Solution:

$R-NH-COH\ce{ ->[{POCl_3}][{\text{Pyridine}}] R-N^+ \equiv C^{-}}$