Thank you for reporting, we will resolve it shortly
Q.
$ R $ is a relation from {11,12,13} to {8,10,12} defined by $ y=x-3 $ . Then $ {{R}^{-1}} $ is
JamiaJamia 2008
Solution:
Since R is a relation from {11,12, 13} to {8, 10,12} defined by $ y=x-3\Rightarrow x-y=3 $ $ \therefore $ $ R=\{(11,8),(13,10)\} $ $ \Rightarrow $ $ {{R}^{-1}}=\{(8,11),(10,13)\} $