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Q. $ R $ is a relation from {11,12,13} to {8,10,12} defined by $ y=x-3 $ . Then $ {{R}^{-1}} $ is

JamiaJamia 2008

Solution:

Since R is a relation from {11,12, 13} to {8, 10,12} defined by $ y=x-3\Rightarrow x-y=3 $ $ \therefore $ $ R=\{(11,8),(13,10)\} $ $ \Rightarrow $ $ {{R}^{-1}}=\{(8,11),(10,13)\} $