1. Tardigrade
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  3. Chemistry
  4. Quantum numbers for some electrons are given below A: n=4, l=1 B: n=4, l=0 C: n=3, l=2 D: n=3, l=1 The correct increasing order of energy of electrons

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Q. Quantum numbers for some electrons are given below
A: $n=4, l=1$
B: $n=4, l=0$
C: $n=3, l=2$
D: $n=3, l=1$
The correct increasing order of energy of electrons

Structure of Atom

Solution:

Energy $=(n+l)$
$A=n=4 \,\,\, l=1 \,\,\, =4+1=5$
$B=n=4 \,\,\, l=0 \,\,\, =4+0=4$
$C=n=3 \,\,\, l=2 \,\,\, =3+2=5$
$D=n=3 \,\,\, l=1 \,\,\, =3+1=4$
According to Pauli exclusion principle
(1) Larger the $( n + l )$; larer will be energy
(2) Same value of $( n + l )$; smaller $n$; more will be energy
$\therefore D < B < C < A$