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Q.
Quantity of electricity required to reduced $0.1$ mole of $Cr_{2}O_{7}^{- 2}$ to $Cr^{+ 3}$ completely is:-
NTA AbhyasNTA Abhyas 2022
Solution:
$1$ mole of $Cr _2 O _7^{-2}$ required $6$ moles of electrons
$\therefore 0.1$ mole $Cr _2 O _7^{-2}$ will required $0.6$ moles of electrons
$0.6$ mole $e ^{-}=0.6 \times 96500= 57900\, C $ Charge