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Q. Pure enantiomericacid+optically active alcohol having chiral $C$ atom $\rightarrow$ ?
The product will be:

Organic Chemistry – Some Basic Principles and Techniques

Solution:

$(+) RCOOH +(-) R ^{\prime} OH \rightarrow(+)(-) RCOOR ^{\prime}$
Pure enantiomeric acid (O.A. alcohol) (O.A. ester)