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  4. Propyne xrightarrow[Hg2SO4]HgSO4 A. Compound A is

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Q. Propyne $\xrightarrow[Hg_2SO_4]{HgSO_4} A$. Compound $A$ is

Hydrocarbons

Solution:

$CH_3 - C \equiv CH \xrightarrow[H_2SO_4]{HgSO_4} \underset{\text{2 - Propanone}}{CH_3 - \overset{\underset{||}{O}}{C} - CH_3}$