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  4. Propylene on treatment with HBr/H2O2 provides

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Q. Propylene on treatment with $HBr/H_2O_2$ provides

KEAMKEAM 2019Hydrocarbons

Solution:

Addition of HBr to unsymmetrical alkenes takes place contrary to the markovnikov's rule in presence of peroxide.

Propylene on treatment with $HBr / H _{2} O _{2}$ provides l-bromopropane. In the presence of peroxide $\left( H _{2} O _{2}\right)$, addition of $HBr$ to unsymmetrical alkenes like propylene takes place contrary to the Markovnikov's rule. This happens only with $HBr$ but not with HCl and HI.

Reaction of propylene with $HBr / H _{2} O _{2}$ is as follows

$\underset{Propylene}{CH_3CH=CH_2}+HBr \xrightarrow{H_2O_2} \underset{1 Bromopropane}{CH_3-CH_2CH_2Br}$